Delta E And Delta H Relationship
penangjazz
Nov 29, 2025 · 10 min read
Table of Contents
Let's explore the fascinating connection between delta E (ΔE), representing the change in internal energy of a system, and delta H (ΔH), which signifies the enthalpy change. Understanding their relationship is crucial in grasping thermochemistry, a fundamental area in chemistry and physics. These thermodynamic quantities describe the energy transformations that accompany physical and chemical processes. This article will delve into the definitions of ΔE and ΔH, their relationship, the conditions under which they are similar or different, and practical applications.
Defining Delta E (ΔE): Change in Internal Energy
The internal energy (E) of a system encompasses the total energy possessed by its constituent particles (atoms, molecules, ions). This energy includes:
- Kinetic energy: Arising from the motion of particles (translational, rotational, vibrational).
- Potential energy: Resulting from intermolecular forces, chemical bonds, and interactions within the atoms themselves.
It's important to note that determining the absolute value of internal energy is practically impossible. Instead, we focus on the change in internal energy (ΔE), which represents the difference between the final and initial internal energies of a system during a process:
ΔE = E<sub>final</sub> - E<sub>initial</sub>
A positive ΔE indicates that the system gained energy from its surroundings (endothermic process), while a negative ΔE signifies that the system released energy to its surroundings (exothermic process).
The change in internal energy is dictated by the First Law of Thermodynamics, which states that energy cannot be created or destroyed, only transferred or converted. Mathematically, the First Law is expressed as:
ΔE = q + w
Where:
- q represents the heat exchanged between the system and its surroundings (positive for heat absorbed by the system, negative for heat released).
- w represents the work done on or by the system (positive for work done on the system, negative for work done by the system).
Defining Delta H (ΔH): Enthalpy Change
Enthalpy (H) is a thermodynamic property of a system that is defined as the sum of the system's internal energy (E) and the product of its pressure (P) and volume (V):
H = E + PV
Like internal energy, the absolute value of enthalpy is difficult to measure directly. We are primarily concerned with the change in enthalpy (ΔH), which represents the heat absorbed or released by a system during a process occurring at constant pressure.
ΔH = H<sub>final</sub> - H<sub>initial</sub>
For a process at constant pressure:
ΔH = ΔE + PΔV
Where:
- ΔE is the change in internal energy.
- P is the constant pressure.
- ΔV is the change in volume (V<sub>final</sub> - V<sub>initial</sub>).
Similar to ΔE, a positive ΔH indicates an endothermic process (heat absorbed), and a negative ΔH indicates an exothermic process (heat released). Enthalpy is a state function, meaning its value depends only on the initial and final states of the system, not on the path taken to reach those states.
The Relationship Between ΔE and ΔH
The equation ΔH = ΔE + PΔV explicitly shows the relationship between ΔH and ΔE. It highlights that the enthalpy change is equal to the change in internal energy plus the product of the constant pressure and the change in volume.
The difference between ΔH and ΔE lies in the PΔV term. This term accounts for the work done by the system against the constant external pressure as it expands or the work done on the system as it contracts. Therefore, ΔH accounts for all the heat exchanged in a constant-pressure process, including the energy used to do pressure-volume work.
Conditions Under Which ΔH ≈ ΔE
In many situations, the difference between ΔH and ΔE is small enough to be negligible, and we can approximate ΔH ≈ ΔE. This occurs under the following conditions:
-
Reactions Involving Only Solids and Liquids: For reactions involving only solids and liquids, the change in volume (ΔV) is usually very small. Since ΔV is close to zero, the PΔV term becomes negligible, and ΔH ≈ ΔE. This is because solids and liquids are relatively incompressible.
-
Reactions Where the Number of Moles of Gas Remains Constant: For reactions involving gases, the PΔV term is more significant. However, if the number of moles of gas remains constant during the reaction (i.e., the total number of moles of gaseous reactants equals the total number of moles of gaseous products), then ΔV is approximately zero, and ΔH ≈ ΔE.
-
Reactions Conducted at Relatively Low Pressures: At low pressures, the volume occupied by a gas is larger, and the intermolecular forces are weaker. Therefore, a change in the number of gas molecules has a smaller impact on the overall energy.
Conditions Under Which ΔH ≠ ΔE
The difference between ΔH and ΔE is significant when the following conditions are met:
-
Reactions Involving a Significant Change in the Number of Moles of Gas: When the number of moles of gas increases or decreases during a reaction, ΔV is significant, leading to a notable difference between ΔH and ΔE. This is particularly important in combustion reactions and other reactions where large amounts of gas are produced or consumed.
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Reactions Conducted at High Pressures: At high pressures, the volume occupied by a gas is smaller, and the intermolecular forces are stronger. A change in the number of gas molecules has a greater impact on the overall energy, making the PΔV term more significant.
Calculating ΔH from ΔE and Vice Versa
To calculate ΔH from ΔE, we use the equation:
ΔH = ΔE + PΔV
When dealing with gases, we can often use the ideal gas law (PV = nRT) to relate pressure, volume, and the number of moles. Assuming ideal gas behavior, we can express PΔV as:
PΔV = Δn<sub>g</sub>RT
Where:
- Δn<sub>g</sub> is the change in the number of moles of gas during the reaction (moles of gaseous products - moles of gaseous reactants).
- R is the ideal gas constant (8.314 J/(mol·K)).
- T is the absolute temperature in Kelvin.
Therefore, the equation becomes:
ΔH = ΔE + Δn<sub>g</sub>RT
This equation allows us to calculate ΔH from ΔE if we know the change in the number of moles of gas, the ideal gas constant, and the temperature. Conversely, we can calculate ΔE from ΔH using:
ΔE = ΔH - Δn<sub>g</sub>RT
Examples Illustrating the Relationship
Let's examine a few examples to illustrate the relationship between ΔE and ΔH.
Example 1: Combustion of Methane (CH<sub>4</sub>)
The combustion of methane is a classic example of a reaction where ΔH and ΔE are different. The balanced equation is:
CH<sub>4</sub>(g) + 2O<sub>2</sub>(g) → CO<sub>2</sub>(g) + 2H<sub>2</sub>O(g)
Let's say the change in internal energy (ΔE) for this reaction is -802 kJ/mol at 298 K. To calculate ΔH, we first need to determine Δn<sub>g</sub>:
Δn<sub>g</sub> = (moles of gaseous products) - (moles of gaseous reactants) = (1 + 2) - (1 + 2) = 0
Since Δn<sub>g</sub> = 0, then PΔV = 0, and ΔH = ΔE = -802 kJ/mol. In this specific (and somewhat unusual) example, the change in the number of moles happens to be zero, and therefore they are equal. Now, consider the case where the water is liquid:
CH<sub>4</sub>(g) + 2O<sub>2</sub>(g) → CO<sub>2</sub>(g) + 2H<sub>2</sub>O(l)
Now, Δn<sub>g</sub> = (moles of gaseous products) - (moles of gaseous reactants) = (1) - (1 + 2) = -2
ΔH = ΔE + Δn<sub>g</sub>RT = -802 kJ/mol + (-2 mol)(8.314 J/(mol·K))(298 K) = -802 kJ/mol - 4955.104 J/mol = -802 kJ/mol - 4.955 kJ/mol = -806.955 kJ/mol
In this case, ΔH is significantly different from ΔE due to the change in the number of moles of gas and the subsequent PΔV term. The reaction is exothermic, and the enthalpy change is more negative than the change in internal energy.
Example 2: Decomposition of Calcium Carbonate (CaCO<sub>3</sub>)
The decomposition of calcium carbonate is an example of a reaction where the change in the number of moles of gas is significant.
CaCO<sub>3</sub>(s) → CaO(s) + CO<sub>2</sub>(g)
Let's assume that ΔE for this reaction is +178 kJ/mol at 298 K. To calculate ΔH:
Δn<sub>g</sub> = (moles of gaseous products) - (moles of gaseous reactants) = (1) - (0) = 1
ΔH = ΔE + Δn<sub>g</sub>RT = 178 kJ/mol + (1 mol)(8.314 J/(mol·K))(298 K) = 178 kJ/mol + 2477.572 J/mol = 178 kJ/mol + 2.478 kJ/mol = 180.478 kJ/mol
In this case, ΔH is larger than ΔE because of the increase in the number of moles of gas. The reaction is endothermic, and the enthalpy change is more positive than the change in internal energy.
Example 3: A Reaction Involving Only Liquids
Consider a simple reaction of mixing two liquids where negligible volume change occurs:
A(l) + B(l) → C(l)
In this case, because the volume change is negligible (ΔV ≈ 0), PΔV ≈ 0, and therefore ΔH ≈ ΔE. If the reaction releases 10 kJ/mol of heat (ΔE = -10 kJ/mol), then ΔH will be approximately -10 kJ/mol.
Practical Applications
Understanding the relationship between ΔE and ΔH is crucial in various practical applications, including:
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Calorimetry: Calorimetry is the science of measuring heat flow in chemical and physical processes. Calorimeters are used to measure ΔH directly at constant pressure. However, bomb calorimeters measure heat at constant volume, yielding ΔE. The relationship between ΔE and ΔH allows us to convert between these measurements.
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Industrial Chemistry: In industrial processes, controlling and optimizing energy changes is essential for efficiency and safety. Understanding ΔE and ΔH helps in designing reactors, optimizing reaction conditions, and predicting energy requirements.
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Environmental Science: Understanding the energy changes associated with chemical reactions is crucial for assessing the environmental impact of various processes, such as combustion of fuels and the formation of pollutants.
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Biochemistry: Many biochemical reactions occur at constant pressure in biological systems. Understanding enthalpy changes is important for studying metabolic pathways and enzyme kinetics. For instance, the energy released during the metabolism of glucose can be quantified using enthalpy changes.
Common Misconceptions
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ΔH and ΔE are Always Equal: This is only true under specific conditions, such as when the change in the number of moles of gas is zero or when reactions involve only solids and liquids with negligible volume changes.
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ΔH is Always More Important than ΔE: Both ΔH and ΔE provide valuable information. ΔH is particularly useful for constant-pressure processes, while ΔE is useful for constant-volume processes. The choice of which to use depends on the specific conditions of the reaction or process.
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Enthalpy is Just Heat: Enthalpy is not simply heat; it is a thermodynamic property that includes internal energy and the product of pressure and volume. The enthalpy change at constant pressure is equal to the heat exchanged.
Conclusion
The relationship between delta E (ΔE) and delta H (ΔH) is fundamental to understanding energy changes in chemical and physical processes. While ΔE represents the change in internal energy, ΔH represents the enthalpy change, which accounts for both the change in internal energy and the pressure-volume work. The equation ΔH = ΔE + PΔV links these two quantities. While ΔH ≈ ΔE under certain conditions, such as reactions involving only solids and liquids or when the number of moles of gas remains constant, the difference between them becomes significant when there is a substantial change in the number of moles of gas. Understanding the nuances of this relationship is essential for accurate thermodynamic calculations and practical applications across various scientific and engineering fields. The ability to calculate ΔH from ΔE (and vice versa) is a powerful tool for analyzing and predicting energy transformations in diverse systems.
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